Step-by-step explanation:
The total surface area of cubiod is
[tex] \sf \: 2( l \times b + b \times h + h \times l) \\ \sf \: = 2(30 \times 25+25 \times 20+20 \times 30) \\ \sf \: =2(750+500+600) \\ \sf \: = 2 \times 1850 \\ \sf \: = 3700 {cm}^{2} [/tex]
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Answer:
Given:
Length (l) = 30 cm
breadth (b) = 25 cm
Height (h) = 15 cm
Find the total surface area and lateral surface area of a shoebox
The shoebox is cuboid in shape.
Total surface area of cuboid = 2 (lb + bh+ lh)
= 2[30 (25) + 25 (15) + 30 (15)]
= 2[750 + 375 + 450]
= 2[1575]
= 3150 sq. cm.
So, the Total surface area of cuboid is 3150 sq. cm.
Lateral surface area of cuboid = 2h(l + b)
= 2 (15) (30 + 25)
= 30 (55)
= 1650 sq. cm.
So, the lateral surface area of cuboid is 1650 sq. cm.
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Verified answer
Step-by-step explanation:
The total surface area of cubiod is
[tex] \sf \: 2( l \times b + b \times h + h \times l) \\ \sf \: = 2(30 \times 25+25 \times 20+20 \times 30) \\ \sf \: =2(750+500+600) \\ \sf \: = 2 \times 1850 \\ \sf \: = 3700 {cm}^{2} [/tex]
Hope it helps 〜(꒪꒳꒪)〜
tata bye bye
Answer:
Step-by-step explanation:
Given:
Length (l) = 30 cm
breadth (b) = 25 cm
Height (h) = 15 cm
Find the total surface area and lateral surface area of a shoebox
The shoebox is cuboid in shape.
Total surface area of cuboid = 2 (lb + bh+ lh)
= 2[30 (25) + 25 (15) + 30 (15)]
= 2[750 + 375 + 450]
= 2[1575]
= 3150 sq. cm.
So, the Total surface area of cuboid is 3150 sq. cm.
Lateral surface area of cuboid = 2h(l + b)
= 2 (15) (30 + 25)
= 30 (55)
= 1650 sq. cm.
So, the lateral surface area of cuboid is 1650 sq. cm.