Given,
SI = 10,920
P = ₹70,000
R = 5.2 %
[tex] T = \frac{10920 \times 100}{70000 \times 5.2} [/tex]
[tex] \: \: \: \: = \frac{10920 \times 1000}{70000 \times 52} [/tex]
[tex] = 3 \: years[/tex]
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Verified answer
Given,
SI = 10,920
P = ₹70,000
R = 5.2 %
[tex] T = \frac{10920 \times 100}{70000 \times 5.2} [/tex]
[tex] \: \: \: \: = \frac{10920 \times 1000}{70000 \times 52} [/tex]
[tex] = 3 \: years[/tex]