Answer:
Answer
Ak =a+(k−1)d=5k+1
⇒a+kd−d=5k+1
By compairing, d=5 & a-d=1
a=1+d
a=1+5=6
Sn = n/2 [2a+(n−1)d]
= n/2 [12+(n−1)5]
=n/2 [5n+7]
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Answers & Comments
Answer:
Answer
Ak =a+(k−1)d=5k+1
⇒a+kd−d=5k+1
By compairing, d=5 & a-d=1
a=1+d
a=1+5=6
Sn = n/2 [2a+(n−1)d]
= n/2 [12+(n−1)5]
=n/2 [5n+7]