sakto si kuya . kanang iyang answer
The sum of first 26 terms of the Fibonacci sequence can be found by calculating the (26+2)th Fibonacci number, F(28) and subtracting 1 from the result. The formula is:
F(1) + F(2) + F(3) +…. + F(n) = F(n+2) - 1.
Therefore,
F(1) + F(2) + F(3) +…. + F(26) = F(26 +2) - 1 = F(28) - 1.
By Binet’s formula, F(n) =1/√5[((1+√5)/2)^n − ((1−√5)/2)^n], n >=1.
Therefore, calculating F(28) by Binet’s formula:
F(28) = 1/√5[((1+√5)/2)^28 − ((1−√5)/2)^28]
= 317811.
F(1) + F(2) + F(3) +…. + F(26) = 317811 - 1
= 317810.
the sum of the first 26 terms of the Fibonacci sequence is: 317810.
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sakto si kuya . kanang iyang answer
The sum of first 26 terms of the Fibonacci sequence can be found by calculating the (26+2)th Fibonacci number, F(28) and subtracting 1 from the result. The formula is:
F(1) + F(2) + F(3) +…. + F(n) = F(n+2) - 1.
Therefore,
F(1) + F(2) + F(3) +…. + F(26) = F(26 +2) - 1 = F(28) - 1.
By Binet’s formula, F(n) =1/√5[((1+√5)/2)^n − ((1−√5)/2)^n], n >=1.
Therefore, calculating F(28) by Binet’s formula:
F(28) = 1/√5[((1+√5)/2)^28 − ((1−√5)/2)^28]
= 317811.
Therefore,
F(1) + F(2) + F(3) +…. + F(26) = 317811 - 1
= 317810.
Therefore,
the sum of the first 26 terms of the Fibonacci sequence is: 317810.