Verified answer

Answer:

given,

p(x) = x²-3x²+4x-4

g(x) = x + 1

g(x') = x - 1.

a) Remainder when p(x) ÷ g(x),

x+1 /x²-3x²+4x-4/ x-3x+6

x² +x

- -

_______

-3x²+3x-4

-3x²-3x

+ +

_____

6x-4

6x+6

- -

____

-10 = r(x).

b) Remainder when p(x)÷g(x')

x-1 /x²-3x²+4x-4/ x-3x+2

x² -x

- +

_______

-3x²+5x-4

-3x²+3x

+ -

_______

2x-4

2x-2

- +

_____

-2 = r(x').

Therefore r(x) + r(x') = -10 -2 = -12.

Answer:

-12

Step-by-step explanation: