Verified answer

Here R=10%,N=3 years, CI=331

CI=P(1+R/100)^N-P

=P(1+10/100)^3-P

=P(110/100)^3-P

=P((110/100)^3-1)

=0.331P

Now CI=331

⇒0.331P=331

⇒P=1000

Now, SI=(P⋅R⋅N)/100

=(1000⋅10⋅3)/100

=300.

hope this helps u

ANSWER -

Given:

Compound interest = 331, 

Rate of interest = 10%

Number of year = 3

Calculation:

We know that amount, 

A = P(1 + R/100)n

A= P(1+10/100)³

A= P(11/10)³

∵ CI = A – P

CI= [P(11/10)³] - P

CI= P [(11/10)³ - 1]

CI= P[(11×11×11 - 10×10×10)/ 10×10×10]

CI= P(331/1000)

But According to the question, CI = 331

331= P(331/1000)

⇒ P = 1000