Answer:
To find the sum of the first 20 terms of the arithmetic series 2, 7, 12, ..., we can use the formula:
S_n = n/2 * [2a + (n-1)d]
where S_n is the sum of the first n terms of the series, a is the first term, d is the common difference, and n is the number of terms.
In this case, a = 2, d = 5 (since each term is 5 more than the previous term), and n = 20. Substituting these values into the formula, we get:
S_20 = 20/2 * [2(2) + (20-1)(5)]
= 10 * [4 + 95]
= 10 * 99
= 990
Therefore, the sum of the first 20 terms of the arithmetic series 2, 7, 12, ... is 990.
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Answer:
To find the sum of the first 20 terms of the arithmetic series 2, 7, 12, ..., we can use the formula:
S_n = n/2 * [2a + (n-1)d]
where S_n is the sum of the first n terms of the series, a is the first term, d is the common difference, and n is the number of terms.
In this case, a = 2, d = 5 (since each term is 5 more than the previous term), and n = 20. Substituting these values into the formula, we get:
S_20 = 20/2 * [2(2) + (20-1)(5)]
= 10 * [4 + 95]
= 10 * 99
= 990
Therefore, the sum of the first 20 terms of the arithmetic series 2, 7, 12, ... is 990.