Answer:
Step-by-step explanation:
[tex] s_{n} = \frac{n}{2} |2a + (n - 1)d| \\ \\ = \frac{179}{2} |2 \times 105 + (179 - 1)5| \\ \\ = \frac{179}{2} |210 + (178)5| \\ \\ = \frac{179}{2} |210 \times 890| \\ \\ = \frac{179}{2} \times 1100 \\ \\ = 179 \times 550 \\ \\ = 98450[/tex]
Thus, the sum of all natural numbers lying between 100 and 1000 , which are multiples of 5 is 98450 .
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Verified answer
Answer:
98450
Step-by-step explanation:
Multiples of 5 are 5,10,15,...... between 100 & 1000 are 105,1,0,………., 995
a=105
d=5
l=995
an=a+(n−1)d
⇒995=105+(n−1)5
⇒995=100±5(n−1)
⇒895=5n
⇒n=179
[tex] s_{n} = \frac{n}{2} |2a + (n - 1)d| \\ \\ = \frac{179}{2} |2 \times 105 + (179 - 1)5| \\ \\ = \frac{179}{2} |210 + (178)5| \\ \\ = \frac{179}{2} |210 \times 890| \\ \\ = \frac{179}{2} \times 1100 \\ \\ = 179 \times 550 \\ \\ = 98450[/tex]
Answer:
Thus, the sum of all natural numbers lying between 100 and 1000 , which are multiples of 5 is 98450 .