find the solution of the following quadratic equations using the best method
1.x²+7×=0
2.6s²+18s+0
3.x²-2×=3
1.x²+7×=0
2.6s²+18s+0
3.x²-2×=3
Add an Answer
More Questions From This User See All
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
1.x²+7x=0
x(x+7)=0
x=0
x+7=0
x1= -7
x2=0
2.6s²+18s=0
6s(s+3)=0
s(s+3)=0
s=0
s+3=0
s1= -3
s2= 0
3.x²-10x+25=0
(x-5)²=0
x-5=0
x=5
Step-by-step explanation:
CORRECT ME IF I'M WRONG