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diy2
@diy2
June 2022
2
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find the smallest number which when divided by 6,7 or 8 will leave remainder 5 in each case.
a) 47 b)173 c)53 d)60
Answers & Comments
ffb
Prime factorization of 6 = 2 * 3
Prime factorization of 7 = 7
Prime factorization of 8 = 2 * 2 * 2
LCM(6,7,8) = 168.
The smallest number that when divided by 6,7,8 will leave remainder 5 in each case = 168 + 5 = 173.
Therefore the smallest number = 173.
Hope this helps!
4 votes
Thanks 29
siddhartharao77
For this problem this is good enough to understand
diy2
LCM is 84
diy2
tell me LCM of 6,7,8
siddhartharao77
LCM of 6,7,8 = 168
josegeorge51p36iz9
TX for the helping hand
haricharan3
173
mohdAfridi111
173
ankit358
very nice and clean
hemu18
173
sukhdeep1440p2rbs3
it was easy question
siddhartharao77
Verified answer
It is 173
173/6 gives remainder 5
173/7 gives remainder 5
173/8 gives remainder 5
10 votes
Thanks 34
diy2
8= 2,2,2
siddhartharao77
Thanks
josegeorge51p36iz9
TX for the helping hand
sukhdeep1440p2rbs3
it was a easy question
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Answers & Comments
Prime factorization of 7 = 7
Prime factorization of 8 = 2 * 2 * 2
LCM(6,7,8) = 168.
The smallest number that when divided by 6,7,8 will leave remainder 5 in each case = 168 + 5 = 173.
Therefore the smallest number = 173.
Hope this helps!
Verified answer
It is 173173/6 gives remainder 5
173/7 gives remainder 5
173/8 gives remainder 5