Verified answer

SLOPE

[tex]__________________________[/tex]

Slope is represented as m, it is the steepness of a line. The slope of a graph is determined by using the formula [tex]\sf \frac{rise}{run}[/tex] but when two points are given we use another formula:

[tex]\sf m = \frac{y_2 \ - \ y_1}{x_2 \ - \ x_1}[/tex]

[tex]\mathbb{SOLUTION:}[/tex]

[tex]\sf 1. \ (\stackrel {x_1} 3,\stackrel {y_1} 7) \ and \ (\stackrel {x_2} 9, \stackrel {y_2} 8)[/tex]

[tex]\sf m = \frac{8 \ - \ 7}{9 \ - \ 3}[/tex]

[tex]\sf m = \boxed{\sf \frac{1}{6}}[/tex]

[tex]\sf 2. \ (\stackrel {x_1} -6,\stackrel {y_1} 5) \ and \ (\stackrel {x_2} 3, \stackrel {y_2} 1)[/tex]

[tex]\sf m = \frac{1 \ - \ 5}{3 \ - \ (-6)}[/tex]

[tex]\sf m = \boxed{\sf - \frac{4}{9}}[/tex]

[tex]\sf 3. \ (\stackrel {x_1} 4,\stackrel {y_1} 6) \ and \ (\stackrel {x_2} 6, \stackrel {y_2} {-4})[/tex]

[tex]\sf m = \frac{(-4) \ - \ 6}{6 \ - \ 4}[/tex]

[tex]\sf m = \frac{-10}{2}[/tex]

[tex]\sf m = \boxed{\sf -5}[/tex]

[tex]\sf 4. \ (\stackrel {x_1} 0,\stackrel {y_1} 7) \ and \ (\stackrel {x_2} 1, \stackrel {y_2} {4})[/tex]

[tex]\sf m = \frac{4 \ - \ 7}{1 \ - \ 0}[/tex]

[tex]\sf m = \frac{-3}{1}[/tex]

[tex]\sf m = \boxed{\sf -3}[/tex]

[tex]\sf 5. \ (\stackrel {x_1} {10},\stackrel {y_1} {-5}) \ and \ (\stackrel {x_2} {-5}, \stackrel {y_2} {-3})[/tex]

[tex]\sf m = \frac{(-3) \ - \ (-5)}{(-5) \ - \ 10}[/tex]

[tex]\sf m = \boxed{\sf - \frac{2}{15}}[/tex]