Answer:
The nature of quadratic equation is no real roots.
Step-by-step explanation:
Given : Quadratic equation 2x²=a–4x
To find : Nature of the roots of quadratic equation?
Solution :
To determine the nature we find discriminant, D=b2−4ac
1) If D<0, no real roots.
2) If D=0, two equal real roots.
3) If D>0, two distinct real roots.
Now, we find discriminant.
2x²–4x+a=0
Here, a=2,b=-4,c=a(1)
D=(-4)²–4(2) (a)
D= 16–8a
D= 8a
So, D<0 there is no real roots.
Therefore, The nature of quadratic equation is no real roots.
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Answers & Comments
Answer:
The nature of quadratic equation is no real roots.
Step-by-step explanation:
Given : Quadratic equation 2x²=a–4x
To find : Nature of the roots of quadratic equation?
Solution :
To determine the nature we find discriminant, D=b2−4ac
1) If D<0, no real roots.
2) If D=0, two equal real roots.
3) If D>0, two distinct real roots.
Now, we find discriminant.
2x²–4x+a=0
Here, a=2,b=-4,c=a(1)
D=(-4)²–4(2) (a)
D= 16–8a
D= 8a
So, D<0 there is no real roots.
Therefore, The nature of quadratic equation is no real roots.