Answer:
-5.83(approx.) and -0.67(approx.)
Step-by-step explanation:
using shree dharacharya:
roots can be
where a=coeffecient of
b=coeffecient of x
c=constant term
so after solving them, the roots will be -
(-7+4.66)/2 and (-7+4.66) /2
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Answers & Comments
Answer:
-5.83(approx.) and -0.67(approx.)
Step-by-step explanation:
using shree dharacharya:
roots can be![\frac{-b+\sqrt{b^{2} -4ac} }{2a} and \frac{-b-\sqrt{b^{2} -4ac} }{2a} \frac{-b+\sqrt{b^{2} -4ac} }{2a} and \frac{-b-\sqrt{b^{2} -4ac} }{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B%5Csqrt%7Bb%5E%7B2%7D%20-4ac%7D%20%7D%7B2a%7D%20%20and%20%5Cfrac%7B-b-%5Csqrt%7Bb%5E%7B2%7D%20-4ac%7D%20%7D%7B2a%7D)
where a=coeffecient of![x^{2} x^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D)
b=coeffecient of x
c=constant term
so after solving them, the roots will be -
(-7+4.66)/2 and (-7+4.66) /2