Answer:
✓16×5=4✓5 units
scoring exilent marks in exams
8.94 units
Step-by-step explanation:
we know that eq of a circle is
(x-h)^2 + (y- k)^2 = r^2
where (h,k) is the centre
so eq becomes (x-3)^2 + (y- 2 )^2 = r^2
circle is passing through the point (-5,6), so if we subsitutue those values in eq we get the radius.
(-5-3)^2+(6-2)^2=r^2
(-8)^2 + (4)^2 = r^2
64+16= r^2
r= sqrt(80)= 8.94
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Answer:
✓16×5=4✓5 units
scoring exilent marks in exams
Answer:
8.94 units
Step-by-step explanation:
we know that eq of a circle is
(x-h)^2 + (y- k)^2 = r^2
where (h,k) is the centre
so eq becomes (x-3)^2 + (y- 2 )^2 = r^2
circle is passing through the point (-5,6), so if we subsitutue those values in eq we get the radius.
(-5-3)^2+(6-2)^2=r^2
(-8)^2 + (4)^2 = r^2
64+16= r^2
r= sqrt(80)= 8.94