Answer:
I think you mean the roots or zeroes. Because it is already a quadratic polynomial.
So here is the solution
6x² - 13x + 6
6x² -12x - x + 6
6x(x - 6) - 1(x - 6)
(6x - 1)(x - 6)
Now (6x - 1)(x - 6) = 0
Either 6x - 1 = 0
x =1/6
Or x - 6 = 0
. x = 6
Therefore, the two zeroes are 1/6 and 6
Hope it helps!
Stay blessed ✨
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Answers & Comments
So here is the solution
6x² - 13x + 6
6x² -12x - x + 6
6x(x - 6) - 1(x - 6)
(6x - 1)(x - 6)
Now (6x - 1)(x - 6) = 0
Either 6x - 1 = 0
x =1/6
Or x - 6 = 0
. x = 6
Therefore, the two zeroes are 1/6 and 6
Answer:
I think you mean the roots or zeroes. Because it is already a quadratic polynomial.
So here is the solution
6x² - 13x + 6
6x² -12x - x + 6
6x(x - 6) - 1(x - 6)
(6x - 1)(x - 6)
Now (6x - 1)(x - 6) = 0
Either 6x - 1 = 0
x =1/6
Or x - 6 = 0
. x = 6
Therefore, the two zeroes are 1/6 and 6
Hope it helps!
Stay blessed ✨