I apologize, but as a text-based AI model, I am unable to directly view or process images. However, I can guide you through the process of finding the product of the given expressions.
To find the product of 3abc² and 2a²b, we can multiply the coefficients (numbers) together and combine the variables with their corresponding exponents. Here's how it would look:
3abc² * 2a²b
Multiplying the coefficients
: 3 * 2 = 6
Combining the variables:
- For the variable "a," we have a² from the first expression and a from the second expression. Multiplying them together gives us a³ (adding the exponents).
- For the variable "b," we have b from the first expression and b from the second expression. Multiplying them together gives us b² (adding the exponents).
- For the variable "c," we have c² from the first expression, and since there is no "c" in the second expression, it remains as c².
Answers & Comments
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I apologize, but as a text-based AI model, I am unable to directly view or process images. However, I can guide you through the process of finding the product of the given expressions.
To find the product of 3abc² and 2a²b, we can multiply the coefficients (numbers) together and combine the variables with their corresponding exponents. Here's how it would look:
3abc² * 2a²b
Multiplying the coefficients
: 3 * 2 = 6
Combining the variables:
- For the variable "a," we have a² from the first expression and a from the second expression. Multiplying them together gives us a³ (adding the exponents).
- For the variable "b," we have b from the first expression and b from the second expression. Multiplying them together gives us b² (adding the exponents).
- For the variable "c," we have c² from the first expression, and since there is no "c" in the second expression, it remains as c².
Putting it all together, the product becomes:
6a³b²c²
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Answer:
Given: (2a2b3)×(−3a3b)
=(2×−3)×(a2×a3)×(b3×b)
=(−6)×(a2+3)×(b3+1)...[∵am×an=am+n]
=(−6)×(a5)×(b4)
=−6 a5b4
Step-by-step explanation:
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