This is answer
3a³-14a²-26a+12
=(a+−6)(3a2+4a+−2)
=(a)(3a2)+(a)(4a)+(a)(−2)+(−6)(3a2)+(−6)(4a)+(−6)(−2)
=3a3+4a2−2a−18a2−24a+12
=3a3−14a2−26a+12
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This is answer
3a³-14a²-26a+12
=(a+−6)(3a2+4a+−2)
=(a)(3a2)+(a)(4a)+(a)(−2)+(−6)(3a2)+(−6)(4a)+(−6)(−2)
=3a3+4a2−2a−18a2−24a+12
=3a3−14a2−26a+12