Answer:

Given:

Height of the object, h = 5 cm

Object distance, u = 10 cm

Focal length, f = 6 cm

Applying lens formula, we get:

1/v 1/u = 1/f (v = Image distance)

1/v 1/(10) = 1/6

or, v = 15 cm

Thus, the image is formed at a distance of 15 cm behind the convex lens (on the right side).

Now

Magnification, m = v/u = h'/h

m = 15/(10)

m = 1.5

The value of magnification is negative; therefore, the image will be real and inverted.

Explanation:

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Answer:

Explanation:

According to question:-

Object distance = u = -5 cm

Focal Length = f = +10 cm

By Lens formula -

1/v - 1/u = 1/f

1/v - 1/(-5) = 1/10

1/v = 1/10 - 1/5

1/v = 1-2/10

1/v = -1/10

v = -10 cm

∵ Image is Formed on the same side of lens as the object.

Magnification = m = v/u

                          m = -10/-5
                          m = +2

∵ Image formed is virtual , erect and enlarged.

Note :- Here you have not clarified whether 5 cm is height of object or object distance. I have solved the numerical by perceiving it to be the object distance.

HOPE IT HELPED !