Answer:
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Step-by-step explanation:
Bisection of line segment AB where A(-6, 11) and B(10, -3) is (2, 4)
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Coordinates of the point of bisection are ( 2 , 4 ).
Let A ( -6, 11 ) be A ( x1, y1 ).
Let B ( 10, -3 ) be B ( x2, y2 ).
Let point of bisection be P ( x, y )
By using midpoint theorem,
x = ( x1 + x2 ) ÷ 2
= ( -6 + 10 ) ÷ 2
= 4 ÷ 2
= 2
y = ( y1 + y2 ) ÷ 2
= ( 11 - 3 ) ÷ 2
= 8 ÷ 2
= 4
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Answer:
here is your answer
Step-by-step explanation:
Bisection of line segment AB where A(-6, 11) and B(10, -3) is (2, 4)
I hope it may help you
pls mark me as a brainlliest
Answer:
Coordinates of the point of bisection are ( 2 , 4 ).
Step-by-step explanation:
Let A ( -6, 11 ) be A ( x1, y1 ).
Let B ( 10, -3 ) be B ( x2, y2 ).
Let point of bisection be P ( x, y )
By using midpoint theorem,
x = ( x1 + x2 ) ÷ 2
= ( -6 + 10 ) ÷ 2
= 4 ÷ 2
= 2
y = ( y1 + y2 ) ÷ 2
= ( 11 - 3 ) ÷ 2
= 8 ÷ 2
= 4
Coordinates of the point of bisection are ( 2 , 4 ).