Answer:
pH = 13.69
Explanation:
since NaOH is a strong electrolyte ,it will dissociate completely as follows -
NaOH == Na+ + OH-
conc. 0.5M 0.5M 0.5M
OH- conc. of NaOH is 0.5 , from this you can calculate pOH. Now you apply pOH+pH =14 (At 25 degree centigrade) to calculate pH of 0.5 M NaOH.
So, pOH=-log[OH-] =- log(0.5) =0.3010 Hence, pH=14 - pH =13.69 .
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Answer:
pH = 13.69
Explanation:
since NaOH is a strong electrolyte ,it will dissociate completely as follows -
NaOH == Na+ + OH-
conc. 0.5M 0.5M 0.5M
OH- conc. of NaOH is 0.5 , from this you can calculate pOH. Now you apply pOH+pH =14 (At 25 degree centigrade) to calculate pH of 0.5 M NaOH.
So, pOH=-log[OH-] =- log(0.5) =0.3010 Hence, pH=14 - pH =13.69 .