Find the perimeter of the rectangle if its length is 1 m less than twice the width, and its area is 190m^2.
Please, add the solution.
Co'z this is not discussed on our module.
Please, add the solution.
Co'z this is not discussed on our module.
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Area = length x width
1 = (1W)w
21 = 2w^2 -w
2w^2 -w2W^2 - w -21=0
(2w-7 )(W +3)=0
2W-7=0 or w+3=0
W=7/2 or w=-3
Width cannot be negative.
So width is 7/2=3.5
Then the length is 6
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