Answer:

3x+y+2z

Step-by-step explanation:

given sides,

3z-2x-y

and,4x+y-2z

and,x+y+z

so,perimeter of a triangle=sum of all sides

=(3z-2x-y)+(4x+y-2z)+(x+y+z)=3z-2x-y+4x+y-2z+x+y+z=3z-2z+z-2x+4x+x-y+y+y=2z+3x+y=3x+y+2z

please mark it as brainliest.