Find the output of the following program: #include<stdio.h>
#include<conio.h>
void main()
int x = 10, y = 10, v1, v2;
v1 = x++;
v2=++y;
printf ("value of v1:%d", v1);
printf ("value of v2:%d", v2);
getch();
}
#include<conio.h>
void main()
int x = 10, y = 10, v1, v2;
v1 = x++;
v2=++y;
printf ("value of v1:%d", v1);
printf ("value of v2:%d", v2);
getch();
}
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
Value of v1:10 value of v2:11
Explanation:
x++ is post increment. so first it will store 10 into v1 and then it will increment to 11. so v1 will give output 10 and x will give 11.
++y is pre increment. so first it will increment to 11 and then 11 will store into v2. so v2 will give 11 and y also will give 11.
Verified answer
[tex]{\fbox{\sf{Answer:-}}}[/tex]
OUTPUT:
value of v1:10
value of v2:11
A bit of explanation of your code: