Sum of measures of all angles of a triangle =(n-2)×180°
So sum of all angles of a regular pentagon with n=5sides =(5-2)×180
3×180=540° Each angle measure =sum of all angles/ no of sides= 540/5=108°
Answer 108°
Hope it helped you
Pentagon is a polygon with 5 sides.
Sum of exterior angle of any polygon is 360 degree
For any polygon with N sides exterior angle =360/N
=360/5
=72 degree
Pentagon has 5 exterior angle and each one is 72 degree
Hope it helps........
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Sum of measures of all angles of a triangle =(n-2)×180°
So sum of all angles of a regular pentagon with n=5sides =(5-2)×180
3×180=540° Each angle measure =sum of all angles/ no of sides= 540/5=108°
Answer 108°
Hope it helped you
Pentagon is a polygon with 5 sides.
Sum of exterior angle of any polygon is 360 degree
For any polygon with N sides exterior angle =360/N
=360/5
=72 degree
Pentagon has 5 exterior angle and each one is 72 degree
Hope it helps........
plse mark me as brainliest