How many cubes of side 5 cm can be adjusted in the rectangular box of 20cm x 15cm x 10cm?
Answer
2
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9 Answers
Best

Augustijn de Boer
, BA. Artificial Intelligence & Data Analysis, Radboud University Nijmegen (2020)
Answered Jun 6, 2017
For each box side length, see how many whole cube sides it would fit. Multiply those integers to get the answer.
10/5 = 2
15/5 = 3
20/5 = 4
2×3×4=24
The method described by some others is flawed, because it shows you only how many cubes would fit in the box volumewise. For some box sized 10×15×22.5, following the ‘volume’ approach, you could fit 27 cubes in there. But this is only possible if you are allowed to cut the cubes in half.
The correct way would be:
10/5 = 2
15/5 = 3
22.5/5 = 4.5 (take the integer) = 4
2×3×4 = 24
This box will have some room left over, namely 10×15×2.5 = 375 cm^3, but it is a slab of 2.5 thickness, so you cannot fit any 5×5×5 cubes in there
Answers & Comments
Verified answer
Answer:
The correct option is C 30
Volume of cubical box =
=
5
×
5
×
5
=
125
c
u
c
m
Volume of carton
=
25
×
10
×
15
=
3750
c
u
c
m
No. of boxes
=
V
o
l
u
m
e
o
f
c
a
r
t
o
n
V
o
l
u
m
e
o
f
e
a
c
h
b
o
x
No. of boxes
=
3750
125
No. of boxes
=
30
Answer:
How many cubes of side 5 cm can be adjusted in the rectangular box of 20cm x 15cm x 10cm?
Answer
2
Follow
Request
More
Ad by AhaGuru Education Technology Pvt ltd
Learn Physics – Rotation and Energy in 3 hours!
Understand how to solve rotation and energy problems for various kinds of bodies and connected systems.
Start Now
9 Answers
Best

Augustijn de Boer
, BA. Artificial Intelligence & Data Analysis, Radboud University Nijmegen (2020)
Answered Jun 6, 2017
For each box side length, see how many whole cube sides it would fit. Multiply those integers to get the answer.
10/5 = 2
15/5 = 3
20/5 = 4
2×3×4=24
The method described by some others is flawed, because it shows you only how many cubes would fit in the box volumewise. For some box sized 10×15×22.5, following the ‘volume’ approach, you could fit 27 cubes in there. But this is only possible if you are allowed to cut the cubes in half.
The correct way would be:
10/5 = 2
15/5 = 3
22.5/5 = 4.5 (take the integer) = 4
2×3×4 = 24
This box will have some room left over, namely 10×15×2.5 = 375 cm^3, but it is a slab of 2.5 thickness, so you cannot fit any 5×5×5 cubes in there