Answer:
We know that P=
A
F
, here A=effective area
In first case , P=
mg
=
0.1×0.2
2×10
=1000Pa
In second case , P=
0.05×0.1
=4000Pa
In third case , P=
0.05×0.2
=2000Pa
Solve any question of Mechanical Properties Of Fluids with:-
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Answers & Comments
Answer:
We know that P=
A
F
, here A=effective area
In first case , P=
A
mg
=
0.1×0.2
2×10
=1000Pa
In second case , P=
0.05×0.1
2×10
=4000Pa
In third case , P=
0.05×0.2
2×10
=2000Pa
Solve any question of Mechanical Properties Of Fluids with:-