Verified answer

we know that

• N = 60 and N/2 = 300

The cumulative frequency just greater than 300 is 440 and the corresponding class is 1000 - 2000

Median formula :

Here,

• l denotes lower limit of median class

• h denotes width of median class

• f denotes frequency of median class

• cf denotes cumulative frequency of the class preceding the median class

• N denotes sum of frequency

According to the question,

• median class is 1000 - 2000

so,

• l = 1000,

• h = 1000,

• f = 190,

• cf = cf of preceding class = 250

• N/2 = 300

By substituting all the given values in the formula,

─━─━─━─━─━─━─━─━─━─━─━─━─

Additional Information :-

Mean :-

Using Direct Method

Using Short Cut Method

Assumed Mean Method :-

Answer:

find the median

class interval frequency

0-1000 250

1000-2000 190

2000-3000 100

3000-4000 40

4000-5000 15

5000-6000 5