Answer:
Marks (x) No. of students (f) C.F.
0-10 15 15
10-20 20 35
20-30 25 60
30-40 24 84
40-50 12 96
50-60 31 127
60-70 71 198
70-80 52 250
N = 250
As, N=250⇒
2
N
=
250
As 127 is just greater than 125, therefore median class is 50−60.
Median=l+
f
+C
×h
Here, l=lower limit of median class =50
C=C.F. of the class preceding the median class =96
h= higher limit - lower limit =60−50=10
f= frequency of median class =31
∴median=50+
31
125−96
×10=50+9.35=59.35
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Answer:
Marks (x) No. of students (f) C.F.
0-10 15 15
10-20 20 35
20-30 25 60
30-40 24 84
40-50 12 96
50-60 31 127
60-70 71 198
70-80 52 250
N = 250
As, N=250⇒
2
N
=
2
250
As 127 is just greater than 125, therefore median class is 50−60.
Median=l+
f
2
N
+C
×h
Here, l=lower limit of median class =50
C=C.F. of the class preceding the median class =96
h= higher limit - lower limit =60−50=10
f= frequency of median class =31
∴median=50+
31
125−96
×10=50+9.35=59.35
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