Find the magnitude of the shape obtained by rotating a right triangle around its hypotenuse, assuming that the base and height of the triangle are 7 m and 24 m, respectively.
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Answer:
The double cone so formed by revolving this right-angled triangle ABC about its hypotenuse is shown in the figure.
Area of ΔABC=
The volume of double cone = Volume of cone 1 + Volume of cone 2
=31πr2h1+31πr2h2
=31πr2[h1+h2]=31πr2[DA+DC]
=31×3.14×2.42×5
=30.14 cm3
The surface area of double cone = Surface area of cone 1 + Surface area of cone 2
=πrl1+πrl2
=πr[4+3]=3.14×2.4×7
=52.75 cm2
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