Answer:
first apply exterior angle property then find the other variable finnaly u can find the c variable
The value of
Name the sides
So,
Given
AB || CR, similarly BM || NR
Here AC is transversal.
➝ ∠BAC = ∠ACR = 72° = ∠c
Now
∠QCR + ∠RCA + ∠ACB = 180°
➜ 55° + 72° + ∠ACB = 180°
➜ 127° + ∠ACB = 180°
➜ ∠ACB = 180° - 127°
➜ ∠ACB = 53° = ∠b
Also,
∆ABC sum of three angles is 180°
∠BAC + ∠ACB + ∠ABC = 180°
☞ 72° + 53° + ∠ABC = 180°
☞ 125° + ∠ABC = 180°
☞ ∠ABC = 180° - 125°
☞ ∠ABC = 55° = ∠a
Hence
∠a = 55°
∠a = 55°∠b = 53°
∠a = 55°∠b = 53°∠c = 72°
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Answers & Comments
Answer:
first apply exterior angle property then find the other variable finnaly u can find the c variable
The value of
Step by step explanation
Name the sides
So,
Given
AB || CR, similarly BM || NR
Here AC is transversal.
➝ ∠BAC = ∠ACR = 72° = ∠c
Now
∠QCR + ∠RCA + ∠ACB = 180°
➜ 55° + 72° + ∠ACB = 180°
➜ 127° + ∠ACB = 180°
➜ ∠ACB = 180° - 127°
➜ ∠ACB = 53° = ∠b
Also,
∆ABC sum of three angles is 180°
∠BAC + ∠ACB + ∠ABC = 180°
☞ 72° + 53° + ∠ABC = 180°
☞ 125° + ∠ABC = 180°
☞ ∠ABC = 180° - 125°
☞ ∠ABC = 55° = ∠a
Hence
∠a = 55°
∠a = 55°∠b = 53°
∠a = 55°∠b = 53°∠c = 72°