Answer:

The required number is HCF of 276 and 1242.

276=2×2×3×23=2

2

×3

1

×23

1

1242=2×3×3×3×23=2

1

×3

3

×23

1

HCF of 276 and 1242=2

1

×3

1

×23

1

=138

The required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138.

Answer:

जडजवाहीर नमस्कार I am so glad that 3rd year 3d has been come well I hope is and for you the role of ❤ for and future president india the that is a not important good of world president to the role of that you the world president and how your make write in the and to will world place it the you you is not the only same in but I can make