Verified answer

[tex]{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}[/tex]

[tex]\begin{gathered}\begin{aligned} & \bold{ Formula:} \\ & \quad \boxed{\begin{array}{l} \rm{ F_g= \frac{Gm_1 m_2}{ {r}^{2} } } \end{array}}\end{aligned}\end{gathered}[/tex]

[tex]\begin{gathered}{\begin{array}{l} \large \rm{ \dfrac{6.67 x 10^{-11} N.m^2}{kg^2} }\end{array}}\end{gathered}[/tex]

[tex]\begin{gathered}\begin{aligned} & \bold{Substitute :} \\ & \quad {\begin{array}{l} \tiny\rm{ F_g= \cfrac{6.67 \times {10}^{ - 11} N.m^2/kg \times74kg \times 82.5kg}{ ({0.95m)}^{ \tiny{2}} } } \end{array}}\end{aligned}\end{gathered}[/tex]

[tex]\begin{gathered}\begin{aligned} & \bold{Substitute :} \\ & \quad {\begin{array}{l} \tiny\rm{ F_g= \cfrac{6.67 \times {10}^{ - 11} N.m^2/kg \times6105 {kg}^{2} }{ {0.9025m}^{ \tiny{2}} } } \end{array}}\end{aligned}\end{gathered}[/tex]

[tex]\begin{gathered}{\begin{array}{l} \large \rm{ F_g= \dfrac{4.07 \times {10}^{ - 7} N.m^2}{0.9025} }\end{array}}\end{gathered}[/tex]

[tex]\begin{gathered}{\begin{array}{l} \large \bf{ F_g= \boxed{\bf{4.51 \times 10^{-7} N} }}\end{array}}\end{gathered}[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Final \: \: Answer :}}}}}}[/tex]

The force of gravity between the students is 4.51 x 10⁻⁷ Newtons.