[tex] \large \red{\mathfrak{ Answer} :}[/tex]
NOTE : I am solving this problem from right side. You can can solve it from either side
In circuit diagram,
R8 and R10 are in series with each other while R9 is in parallel to them
Thus, Rs = 10 + 2 = 12 Ω
and,
[tex] \sf \frac{1}{R_p} = \frac{1}{R_s} + \frac{1}{R_9} = \frac{1}{12} + \frac{1}{6} [/tex]
Thus, Rp = 4 Ω
Let this combination of resistors R8, R9 and R10 be named as Ra
The resistor R7 is in parallel resistance with Ra
Thus, Ra + R7 = 4 + 8 = 12 Ω
R6 is in parallel to this whole combination and let us name this whole combination as Rb
Thus,
[tex] \sf\frac{1}{R_b} = \frac{1}{R_6} + \frac{1}{12} = \frac{1}{6} + \frac{1}{12}[/tex]
Rb = 4 Ω
From circuit diagram Rb ad R5 is in series,
Thus, Rb + R5 = 4 + 4 = 8 Ω
R4 is in parallel this combination and
let the resistance be Rc
[tex] \sf\frac{1}{R_c} = \frac{1}{8} + \frac{1}{8}[/tex]
Rc = 4 Ω
Rc and R3 are in series
Thus, Rc + R3 = 4 + 4 = 8 Ω
This 8 ohms is in parallel with R2 and can be named as Rd
[tex] \sf\frac{1}{R_d} = \frac{1}{R_2} + \frac{1}{8} = \frac{1}{8} + \frac{1}{8}[/tex]
Rd = 4 Ω
Rd is in series with R1
[tex] \blue{ \boxed{ \large \sf{ \red{ \bigstar} \green{Equivalent \: Resistance = 10 Ω}} }}[/tex]
[tex] \\ \\ \small{ \red {\bigstar}} \small{ \pmb{ \sf{ \fcolorbox{pink}{back}{ \: \:\: \:\: \: @Saanvigrover2007 \: \:\: \:\: \:}} \red \bigstar}} \\ [/tex]
[tex] \large \red{\mathfrak{Copying \: Wins} :}[/tex]
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[tex] \large \red{\mathfrak{ Answer} :}[/tex]
NOTE : I am solving this problem from right side. You can can solve it from either side
In circuit diagram,
R8 and R10 are in series with each other while R9 is in parallel to them
Thus, Rs = 10 + 2 = 12 Ω
and,
[tex] \sf \frac{1}{R_p} = \frac{1}{R_s} + \frac{1}{R_9} = \frac{1}{12} + \frac{1}{6} [/tex]
Thus, Rp = 4 Ω
Let this combination of resistors R8, R9 and R10 be named as Ra
The resistor R7 is in parallel resistance with Ra
Thus, Ra + R7 = 4 + 8 = 12 Ω
R6 is in parallel to this whole combination and let us name this whole combination as Rb
Thus,
[tex] \sf\frac{1}{R_b} = \frac{1}{R_6} + \frac{1}{12} = \frac{1}{6} + \frac{1}{12}[/tex]
Rb = 4 Ω
From circuit diagram Rb ad R5 is in series,
Thus, Rb + R5 = 4 + 4 = 8 Ω
R4 is in parallel this combination and
let the resistance be Rc
Thus,
[tex] \sf\frac{1}{R_c} = \frac{1}{8} + \frac{1}{8}[/tex]
Rc = 4 Ω
Rc and R3 are in series
Thus, Rc + R3 = 4 + 4 = 8 Ω
This 8 ohms is in parallel with R2 and can be named as Rd
Thus,
[tex] \sf\frac{1}{R_d} = \frac{1}{R_2} + \frac{1}{8} = \frac{1}{8} + \frac{1}{8}[/tex]
Rd = 4 Ω
Rd is in series with R1
Thus,
Req = Rd + R1 = 4 + 6 = 10 Ω
[tex] \blue{ \boxed{ \large \sf{ \red{ \bigstar} \green{Equivalent \: Resistance = 10 Ω}} }}[/tex]
[tex] \\ \\ \small{ \red {\bigstar}} \small{ \pmb{ \sf{ \fcolorbox{pink}{back}{ \: \:\: \:\: \: @Saanvigrover2007 \: \:\: \:\: \:}} \red \bigstar}} \\ [/tex]
[tex] \large \red{\mathfrak{Copying \: Wins} :}[/tex]
NOTE : I am solving this problem from right side. You can can solve it from either side
In circuit diagram,
R8 and R10 are in series with each other while R9 is in parallel to them
Thus, Rs = 10 + 2 = 12 Ω
and,
[tex] \sf \frac{1}{R_p} = \frac{1}{R_s} + \frac{1}{R_9} = \frac{1}{12} + \frac{1}{6} [/tex]
Thus, Rp = 4 Ω
Let this combination of resistors R8, R9 and R10 be named as Ra
The resistor R7 is in parallel resistance with Ra
Thus, Ra + R7 = 4 + 8 = 12 Ω
R6 is in parallel to this whole combination and let us name this whole combination as Rb
Thus,
[tex] \sf\frac{1}{R_b} = \frac{1}{R_6} + \frac{1}{12} = \frac{1}{6} + \frac{1}{12}[/tex]
Rb = 4 Ω
From circuit diagram Rb ad R5 is in series,
Thus, Rb + R5 = 4 + 4 = 8 Ω
R4 is in parallel this combination and
let the resistance be Rc
Thus,
[tex] \sf\frac{1}{R_c} = \frac{1}{8} + \frac{1}{8}[/tex]
Rc = 4 Ω
Rc and R3 are in series
Thus, Rc + R3 = 4 + 4 = 8 Ω
This 8 ohms is in parallel with R2 and can be named as Rd
Thus,
[tex] \sf\frac{1}{R_d} = \frac{1}{R_2} + \frac{1}{8} = \frac{1}{8} + \frac{1}{8}[/tex]
Rd = 4 Ω
Rd is in series with R1
Thus,
Req = Rd + R1 = 4 + 6 = 10 Ω
[tex] \blue{ \boxed{ \large \sf{ \red{ \bigstar} \green{Equivalent \: Resistance = 10 Ω}} }}[/tex]
[tex] \\ \\ \small{ \red {\bigstar}} \small{ \pmb{ \sf{ \fcolorbox{pink}{back}{ \: \:\: \:\: \: @Saanvigrover2007 \: \:\: \:\: \:}} \red \bigstar}} \\ [/tex]