Answer:
i) 64
We have,
64–1=63
63–7=56
56–19=37
37–37=0
Subtraction is performed 4 times.
Hence, cube root of 64 is 4.
(ii) 512
512–1=511
511–7=504
504–19=485
485–37=448
448–61=387
387–91=296
296–127=169
169–169=0
Subtraction is performed 8 times.
Hence, cube root of 512 is 8.
(iii) 1728
1728–1=1727
1727–7=1720
1720–19=1701
1701–37=1664
1664–91=1512
1512–127=1385
1385–169=1216
1216–217=999
999–271=728
728–331=397
397–397=0
Subtraction is performed 12 times.
Hence, cube root of 1728 is 12.
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Verified answer
Answer:
i) 64
We have,
64–1=63
63–7=56
56–19=37
37–37=0
Subtraction is performed 4 times.
Hence, cube root of 64 is 4.
(ii) 512
We have,
512–1=511
511–7=504
504–19=485
485–37=448
448–61=387
387–91=296
296–127=169
169–169=0
Subtraction is performed 8 times.
Hence, cube root of 512 is 8.
(iii) 1728
We have,
1728–1=1727
1727–7=1720
1720–19=1701
1701–37=1664
1664–91=1512
1512–127=1385
1385–169=1216
1216–217=999
999–271=728
728–331=397
397–397=0
Subtraction is performed 12 times.
Hence, cube root of 1728 is 12.