Find the cost of sinking a tube well 350 m deep, having a diameter of 4 m at the rate of Rs 16 per m³. Find also the cost of cementing its inner curved surface at Rs 12 per m²
To find the cost of sinking a tube well 350 m deep with a diameter of 4 m, we need to calculate the volume of the well and then multiply it by the given rate.
The volume of a cylinder (which represents the well) is given by the formula V = πr²h, where r is the radius and h is the height.
Given that the diameter is 4 m, the radius (r) is half of that, which is 2 m. The height (h) is given as 350 m.
Using these values, we can calculate the volume of the well:
V = π(2²)(350)
= 4π(350)
= 1400π m³
Now, we can multiply the volume by the given rate of Rs 16 per m³ to find the cost of sinking the tube well:
Cost of sinking = 1400π * 16
≈ 1400 * 3.14 * 16
≈ 70304 Rs
Therefore, the cost of sinking the tube well is approximately 70304 Rs.
To find the cost of cementing the inner curved surface of the well, we need to calculate the area of the curved surface and then multiply it by the given rate.
The curved surface area of a cylinder is given by the formula A = 2πrh, where r is the radius and h is the height.
Using the same values as before, we can calculate the curved surface area:
A = 2π(2)(350)
= 4π(350)
= 1400π m²
Now, we can multiply the area by the given rate of Rs 12 per m² to find the cost of cementing the inner curved surface:
Cost of cementing = 1400π * 12
≈ 1400 * 3.14 * 12
≈ 52704 Rs
Therefore, the cost of cementing the inner curved surface of the tube well is approximately 52704 Rs.
Answers & Comments
Answer:
To find the cost of sinking a tube well 350 m deep with a diameter of 4 m, we need to calculate the volume of the well and then multiply it by the given rate.
The volume of a cylinder (which represents the well) is given by the formula V = πr²h, where r is the radius and h is the height.
Given that the diameter is 4 m, the radius (r) is half of that, which is 2 m. The height (h) is given as 350 m.
Using these values, we can calculate the volume of the well:
V = π(2²)(350)
= 4π(350)
= 1400π m³
Now, we can multiply the volume by the given rate of Rs 16 per m³ to find the cost of sinking the tube well:
Cost of sinking = 1400π * 16
≈ 1400 * 3.14 * 16
≈ 70304 Rs
Therefore, the cost of sinking the tube well is approximately 70304 Rs.
To find the cost of cementing the inner curved surface of the well, we need to calculate the area of the curved surface and then multiply it by the given rate.
The curved surface area of a cylinder is given by the formula A = 2πrh, where r is the radius and h is the height.
Using the same values as before, we can calculate the curved surface area:
A = 2π(2)(350)
= 4π(350)
= 1400π m²
Now, we can multiply the area by the given rate of Rs 12 per m² to find the cost of cementing the inner curved surface:
Cost of cementing = 1400π * 12
≈ 1400 * 3.14 * 12
≈ 52704 Rs
Therefore, the cost of cementing the inner curved surface of the tube well is approximately 52704 Rs.