Answer:
Step-by-step explanation:
Area of triangle with sides a, b and c and s=2
a+b+c
is
s(s−a)(s−b)(s−c)
.
For triangle with sides 24m, 40m and 32m, s=2
24+40+32
=48m
Area of the triangle with sides 24m, 40m and 32m =
48(48−24)(48−40)(48−32)
=
48×24×8×16
24×2×24×8×8×2
=24×8×2=384m square
s=a+b+c/2, 40+24+32/2, 96/2, 48
a=underroot(48-40)(48-24(48-32),. unferroot 8*24*16, underroot 3072, 16 underroot 6
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Verified answer
Answer:
Step-by-step explanation:
Area of triangle with sides a, b and c and s=2
a+b+c
is
s(s−a)(s−b)(s−c)
.
For triangle with sides 24m, 40m and 32m, s=2
24+40+32
=48m
Area of the triangle with sides 24m, 40m and 32m =
48(48−24)(48−40)(48−32)
=
48×24×8×16
=
24×2×24×8×8×2
=24×8×2=384m square
Answer:
s=a+b+c/2, 40+24+32/2, 96/2, 48
a=underroot(48-40)(48-24(48-32),. unferroot 8*24*16, underroot 3072, 16 underroot 6