Answer:
Hi dear blink hope this helps you have a great day ahead
Step-by-step explanation:
∴ The cost of laying the grass in the triangular field at the rate of Rs 8 per m² is Rs.12296.32.
[tex] \sf \: Solution:[/tex]
Given that
Sides of the triangular field are
Cost of laying grass in a triangular field
= Rs 8 per m2
Let a = 55, b = 60, c = 65
[tex] \bold {Semi- Perimeter = \frac{(a + b + c)}{2} } \\ \\ \sf \:⇒ s = \frac{(55 + 60 + 65)}{2} = \frac{180}{2} = 90. [/tex]
By using Heron’s formula,
Area of ΔBEC
[tex] \sf= \sqrt{ s(s−a)(s−b)(s−c)} \\ \\ \sf \: = \sqrt{90(90−55)(90−60)(90−65)} \\ \\ \sf \: = \sqrt{90 \times 35 \times 30 \times 25} \\ \\ \sf \: = \sqrt{2362500} \\ \\ \sf \red{= 1537 {m}^{2} }[/tex]
Now, Cost of laying grass
= Area of triangle × Cost of laying grass per m2
= 1537×8
= Rs.12296
More info :-
[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} {\boxed{\begin{array}{cc} {\sf{Area \: of \: parallelogram = Base × Altitude }} \\ \\ \sf{ Area \: of \: rectangle = Length × breadth}\\ \\ \sf{ Area \: of \: square = Side × Side } \\ \\ \sf{Area \: of \: cylinder's \: surface = 2πr(h + r)} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered} [/tex]
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Answers & Comments
Answer:
Hi dear blink hope this helps you have a great day ahead
Step-by-step explanation:
∴ The cost of laying the grass in the triangular field at the rate of Rs 8 per m² is Rs.12296.32.
Verified answer
Step-by-step explanation:
[tex] \sf \: Solution:[/tex]
Given that
Sides of the triangular field are
Cost of laying grass in a triangular field
= Rs 8 per m2
Let a = 55, b = 60, c = 65
[tex] \bold {Semi- Perimeter = \frac{(a + b + c)}{2} } \\ \\ \sf \:⇒ s = \frac{(55 + 60 + 65)}{2} = \frac{180}{2} = 90. [/tex]
By using Heron’s formula,
Area of ΔBEC
[tex] \sf= \sqrt{ s(s−a)(s−b)(s−c)} \\ \\ \sf \: = \sqrt{90(90−55)(90−60)(90−65)} \\ \\ \sf \: = \sqrt{90 \times 35 \times 30 \times 25} \\ \\ \sf \: = \sqrt{2362500} \\ \\ \sf \red{= 1537 {m}^{2} }[/tex]
Now, Cost of laying grass
= Area of triangle × Cost of laying grass per m2
= 1537×8
= Rs.12296
More info :-
[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} {\boxed{\begin{array}{cc} {\sf{Area \: of \: parallelogram = Base × Altitude }} \\ \\ \sf{ Area \: of \: rectangle = Length × breadth}\\ \\ \sf{ Area \: of \: square = Side × Side } \\ \\ \sf{Area \: of \: cylinder's \: surface = 2πr(h + r)} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered} [/tex]