Answer:
32 sq. cm.
Step-by-step explanation:
h = 8 cm, b = 8 cm
Area of the triangle = h x b x 1/2
= 8 x 8 x 1/2
= 64/2
= 32 sq. cm.
16[tex]\sqrt{3}[/tex]cm^2
area of a triangle = 1/2 bh [ b:base , h: height]
base, b = 8cm
height, h = [tex]4\sqrt{3}[/tex]
[ NOTE: In an equilateral triangle, the sides are equal. So, the altitude becomes the perpendicular bisector.]
by Pythagoras theorem,
h = [tex]\sqrt{8^{2} - 4^{2 }[/tex] = [tex]\sqrt{48}[/tex] = [tex]4\sqrt{3}[/tex]
Thus, area = 16[tex]\sqrt{3}[/tex] cm^2
Hope this helps :)
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Answers & Comments
Answer:
32 sq. cm.
Step-by-step explanation:
h = 8 cm, b = 8 cm
Area of the triangle = h x b x 1/2
= 8 x 8 x 1/2
= 64/2
= 32 sq. cm.
Answer:
16[tex]\sqrt{3}[/tex]cm^2
Step-by-step explanation:
area of a triangle = 1/2 bh [ b:base , h: height]
base, b = 8cm
height, h = [tex]4\sqrt{3}[/tex]
[ NOTE: In an equilateral triangle, the sides are equal. So, the altitude becomes the perpendicular bisector.]
by Pythagoras theorem,
h = [tex]\sqrt{8^{2} - 4^{2 }[/tex] = [tex]\sqrt{48}[/tex] = [tex]4\sqrt{3}[/tex]
Thus, area = 16[tex]\sqrt{3}[/tex] cm^2
Hope this helps :)