Answer:
The area of the required square is 2.88
In context to the question it is asked to find the area of a square
the data is given as length of diagonal is 2.4m
length of diagonal=2.4cm
Diagonal of a square, whose length of each side is ‘a' cm is a√2 cm.
Here, length of diagonal is 2.4 cm.
a√2 =2.4
by Squaring both sides, we get
[tex]2\times a^{2}=2.4\\[/tex]
But area of a square=
[tex]a^{2}[/tex]
Area of the required square=[tex]a^{2}[/tex]
=[tex]\frac{5.76}{2}\\=2.88[/tex]
Therefore, the area of the required square=(2.88) sq.cm
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Verified answer
Answer:
The area of the required square is 2.88
In context to the question it is asked to find the area of a square
the data is given as length of diagonal is 2.4m
length of diagonal=2.4cm
Diagonal of a square, whose length of each side is ‘a' cm is a√2 cm.
Here, length of diagonal is 2.4 cm.
a√2 =2.4
by Squaring both sides, we get
[tex]2\times a^{2}=2.4\\[/tex]
But area of a square=
[tex]a^{2}[/tex]
Area of the required square=[tex]a^{2}[/tex]
=[tex]\frac{5.76}{2}\\=2.88[/tex]
Therefore, the area of the required square=(2.88) sq.cm