Verified answer

Answer:

GIVEN:-

ABCD is a rectangle

with length (AB) = 20 CM

breadth (BC) = 15 CM

And

Triangle AED

Base (AD)= 15 CM

Height (FE) = 10 CM

Solution

[tex] \tt \: Total \: \: Area \: \: of \: \: figure = length \times beadth \\ = 20 \times 15 \\ \tt = 300 \: {cm}^{2} [/tex]

[tex] \tt \: Area \: \: of \: \: triangle = \frac{1}{2} \times base \times height[/tex]

[tex] \tt \: Area \: \: of \: \: triangle = \frac{1}{2} \times base \times height \\ \\ \tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times 15 \times 10 \\ \\ \tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 75 \: {cm}^{2} [/tex]

[tex] \tt \: Area \: \: of \: \: shaded \: \: region = 300 - 75 \\ \tt \: = 225 \: {cm}^{2} [/tex]

Hope it will help you.