Answer:
in first ∆
b =7cm
l=12cm
in second ∆
b=15cm
area of both ∆ = 1/2×b×l + 1/2×b×l
=1/2×7×12 + 1/2×15×12
=1/2(7×12 + 15×12)
=1/2(84+180)
=1/2(264)
=132cm^2
area of triangle ABC + area of triangle ADC
area of triangle ADC= 1/2 base × height
=1/2×7×12
=42sq cm
area of triangle ABC=1/2base×height
=1/2×15×12
=180sq cm
area of ABC+area of ADC
= 180+42
= 222sq cm
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Answers & Comments
Answer:
in first ∆
b =7cm
l=12cm
in second ∆
b=15cm
l=12cm
area of both ∆ = 1/2×b×l + 1/2×b×l
=1/2×7×12 + 1/2×15×12
=1/2(7×12 + 15×12)
=1/2(84+180)
=1/2(264)
=132cm^2
Answer:
area of triangle ABC + area of triangle ADC
area of triangle ADC= 1/2 base × height
=1/2×7×12
=42sq cm
area of triangle ABC=1/2base×height
=1/2×15×12
=180sq cm
area of ABC+area of ADC
= 180+42
= 222sq cm