Answer:
Given: ABCD is a square with side 20 cm. To find: Area of given figure. Therefore, the area of the given figure is 314 cm².
Given that
ABCD is a square where AB = BC= CD= AD = 20cm.
radius of semi circle is half of side of square.
So, radius = ½ of 20 = 10cm.
Total area = Area of square ABCD + twice of Area of one semicircle
Total area = (side)² + 2 × ½πr²
= (20)² + π (10)²
= 400+ 3.14× 100
= 400+ 314
= 714 cm²
Total area of figure is 714 cm²
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Answer:
Given: ABCD is a square with side 20 cm. To find: Area of given figure. Therefore, the area of the given figure is 314 cm².
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Given that
ABCD is a square where AB = BC= CD= AD = 20cm.
radius of semi circle is half of side of square.
So, radius = ½ of 20 = 10cm.
Total area = Area of square ABCD + twice of Area of one semicircle
Total area = (side)² + 2 × ½πr²
= (20)² + π (10)²
= 400+ 3.14× 100
= 400+ 314
= 714 cm²
Total area of figure is 714 cm²
❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Thanks...