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Answer:

Given equation of circle is:

x2+y2=a2

⇒y2=a2−x2

⇒y=a2−x2

∴ Area of circle =4×Area of first quadrant

=4∫0aydx

=4∫0aa2−x2dx

=4[2xa2−x2+2a2sin−1ax]0a

=4[0+2a2sin−1aa−(0+2a2sin−1a0)]

=4[2a2sin−11−0]

=2a2⋅2π

=πa2 square units.

Answer:

Hi dear I am Aayush Malik