The surface area A measured in square centimeters is below.
A=840−−√+16≈66.5965 cm2
Explanation:
The Pyramids at Giza are square-based pyramids, or tetrahedrons. In this case the base b=4 cm has an area Ab=4×4=16 square cm and the height is h=6 cm.
The four slanted triangle surfaces 4As depend on the base and height somehow. They are all isosceles triangles with base b=4 cm and some slant height.
Imagine cutting the pyramid in half from the point down to the base. The cross-section has two right triangles with base b=4 cm and height h=6 cm. The hypotenuse is the slant height H=(b2)2+h2−−−−−−−−√ being sought.
Answers & Comments
Answer:
The surface area A measured in square centimeters is below.
A=840−−√+16≈66.5965 cm2
Explanation:
The Pyramids at Giza are square-based pyramids, or tetrahedrons. In this case the base b=4 cm has an area Ab=4×4=16 square cm and the height is h=6 cm.
The four slanted triangle surfaces 4As depend on the base and height somehow. They are all isosceles triangles with base b=4 cm and some slant height.
Imagine cutting the pyramid in half from the point down to the base. The cross-section has two right triangles with base b=4 cm and height h=6 cm. The hypotenuse is the slant height H=(b2)2+h2−−−−−−−−√ being sought.
As=12bH
Find the Surface Area
A=4As+Ab=4(12bH)+b2
A=4(12b(b2)2+h2−−−−−−−−√)+b2
A=4(42(42)2+62−−−−−−−−√)+42
A=84+36−−−−−√+16=840−−√+16.
I hope it helps:)
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