find the area of a rectangle whose sides measure
a)(x+1)and(x-1);
b)(2x+1)and(2x-1);
c)(x-5)and(x-5);
d)(2a+7)(2a-7)
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a)(x+1)and(x-1);
b)(2x+1)and(2x-1);
c)(x-5)and(x-5);
d)(2a+7)(2a-7)
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Answer:
A) x^2 - 1
B) 4x^2 - 1
C) x^2 - 10x +25
D) 4a^2 - 49
Step-by-step explanation:
A) A=L * W
A= (x+1)(x-1)
A=( x^2) - x +x - 1
A= x^2 - 1
B) A=L*W
A= (2x+1)(2x-1)
A=4x^2 - 1
C) A= L*W
A=(x-5)(x-5)
A=(x^2) - 5x - 5x +25
A=x^2 - 10x +25
D) A=L*W
A=(2a+7)(2a-7)
A=(4a^2) - 14a +14a - 49
A= 4a^2 - 49
*note : "^" stands for exponent
x^2 same as x squared or x raised to 2
Hope it helps.
Answer:
A) x^2 - 1
B) 4x^2 - 1
C) x^2 - 10x +25
D) 4a^2 - 49
Step-by-step explanation:
A) A=L * W
A= (x+1)(x-1)
A=( x^2) - x +x - 1
A= x^2 - 1
B) A=L*W
A= (2x+1)(2x-1)
A=4x^2 - 1
C) A= L*W
A=(x-5)(x-5)
A=(x^2) - 5x - 5x +25
A=x^2 - 10x +25
D) A=L*W
A=(2a+7)(2a-7)
A=(4a^2) - 14a +14a - 49
A= 4a^2 - 49
*note : "^" stands for exponent
x^2 same as x squared or x raised to 2
Hope it helps.
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