Find the area of a circle whose circumference is same as the perimeter of a square of side 88cm.koi answer batao na..plz. Created by xXitzMissUniqueXx. Math

Answer:9856 square cmStep-by-step explanation:perimeter of a square =88(side)×4=352perimeter of circle (circumference)=perimeter of square ...(given)circumference=352 c=2πrc=2×22/7×r352=2×22/7× RR=352×7 / 2×22=56 cm area of a circle =πr squarearea of a circle =πr square= 22/7× 56×56area of a circle =πr square= 22/7× 56×56= 9856 square cm area of the circle is 9856 square cm (cm square)

Find the area of a circle whose circumference is same as the perimeter of a squa...

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$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large\underline{\green{\bf Given :-}}$

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Circumference of circle is same as the perimeter of a square

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Side of square = 88 cm

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$\large\underline{\red{\bf To \: Find :-}}$

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Area of a circle

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$\large\underline{\orange{\bf Solution :-}}$

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$\underline{\bold{\texttt{Perimeter of square :}}}$

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➠ 4(Side) ⚊⚊⚊⚊ ⓵

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$\underline{\bold{\texttt{Perimeter of given square :}}}$

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Perimeter = Perimeter

Side = 88 cm

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Putting these values in ⓵

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➜ 4(Side)

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➜ 4(88)

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➨ 352 cm ⚊⚊⚊⚊ ⓶

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Hence the perimeter of square is 352 cm

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$\underline{\bold{\texttt{Circumference of circle :}}}$

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➠ 2πr ⚊⚊⚊⚊ ⓷

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Given that circumference of circle is same as the perimeter of a square

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⟮ So, from ⓶ & ⓷ we get ⟯

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➜ 2πr = 352

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➜ πr = 176

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➜ $\sf \dfrac { 22 } { 7 } × r = 176$

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➜ $\sf \dfrac { 1 } { 7 } × r = \dfrac { 176 } { 22 }$

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➜ $\sf \dfrac { 1 } { 7 } × r = 8$

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➜ r = 8 × 7

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➨ r = 56 cm

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Thus the radius of circle is 56 cm

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$\underline{\bold{\texttt{Area of circle :}}}$

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➠ πr² ⚊⚊⚊⚊ ⓸

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Where,

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r = Radius of circle

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$\underline{\bold{\texttt{Area of given circle :}}}$

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r = 56 cm

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Putting the above value in ⓸

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➜ πr²

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➜ π(56)²

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➜ $\sf \dfrac { 22 } { \cancel 7 } × \cancel { 56} × 56$

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➜ 22 × 8 × 56

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➜ 176 × 56

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➨ 9856 sq. cm.

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Hence the area of circle is 9856 sq. cm.

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Answers & Comments

perimeter of a square =88(side)×4=352

=56 cm

area of the circle is 9856 square cm (cm square)

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