[tex]\huge\bf{{\color{indigo}{A}}{\color{maroon}{ñ}}{\red{s}}{\color{red}{w}}{\color{orange}{ê}}{\color{go}{Я࿐}}}[/tex]

Answer:

the ac resistance of semiconductor diode having a forward bias of 200 mv and reverse saturation current of 1 microampere at room temperature is 91.32 ohms

Explanation:  

We know that Diode current is given by Shockley's equation,

Id=Is[e^(\frac{Vd}{n*Vt})-1]

Where Id is the forward current,

Is: reverse saturation current

Vd is the voltage applied across diode

Vt: thermal voltage i.e. 26mV at room temperature

Id=10^-6[e^((200*10^-3)/(1*26*10^-3))-1]

Id=2.19mA

Hence the AC resistance is= 200/2.19=91.32 ohms

[tex]\huge{\underline{\underline{\mathtt{\purple{☠itz.king}\green{}\pink{}\blue{}\purple{}\red{☠}}}}}[/tex]

Explanation:

Hope this helps you............