Answer:
[tex]50 + 30 + x = sum \: of \: triangle \\ 50 + 30 + x = 180 \\ 80 + x = 180 \\ x = 180 - 80 \\ x = 100 \\ \\ alt \: int \: angle \\ \\ angle3 \: = 100 + ang3 = 180 \\ lp \\ \\ angle3 = 80 \\ so \: \\ x = 100[/tex]
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Answers & Comments
[tex]Sum \: of interior \: angles \: of \: \\ a \: triangle = 180°[/tex]
[tex]∠ A+ ∠B + ∠C = 180° \\ \\ 50° + 30° + ∠ C= 180° \\ \\ 80 ° + ∠C = 180° \\ \\ ∠ = 180° - 80° \\ \\ ∠C = 100°[/tex]
Answer:
[tex]50 + 30 + x = sum \: of \: triangle \\ 50 + 30 + x = 180 \\ 80 + x = 180 \\ x = 180 - 80 \\ x = 100 \\ \\ alt \: int \: angle \\ \\ angle3 \: = 100 + ang3 = 180 \\ lp \\ \\ angle3 = 80 \\ so \: \\ x = 100[/tex]