[tex]{\huge{\colorbox {lavenderblush}{✯Answer✯࿐}}}[/tex]
Solution:
AB represent a 2 digit number with A
at 10s place and B at units place. We are multiplying AB with AB.
• A and B can take any values from 0 to 9.
But If We multiply B by B to get B itself at the units place of the product,
⚫ B can be 0, 1, 5, 6.
• Also A should be at the 10s place, therefore middle term should not have any carry over.
Middle term is AB + AB = C
Therefore B cannot be 5 or 6.
Also A cannot be 5 or 6.
. Therefore A and B can be 0 or 1
If we assume B and C to be different numbers, B cannot be 0, as this makes C also 0.
Therefore, B = 1
. Then A also 1 • C=AB+ BA = 2
Answer:
Sup Kakashi
Step-by-step explanation:
To solve the cryptogram AB×BA = ACB, we need to find the values of A, B, and C that satisfy the equation.
Let's break down the equation: AB×BA = ACB.
We can see that the product of AB and BA equals ACB.
Let's assign variables to each digit: A, B, and C.
To find the values, we can start by multiplying the ones digit of AB (B) with the ones digit of BA (A). This should give us the ones digit of ACB.
From the equation, we have B × A = C.
Now, let's look at the tens digit. When we multiply the tens digit of AB (A) with the ones digit of BA (A), we should get the tens digit of ACB.
From the equation, we have A × A = A.
Lastly, let's consider the hundreds digit. The hundreds digit of ACB is equal to the product of the tens digit of AB (B) and the tens digit of BA (B).
From the equation, we have B × B = B.
Based on this analysis, we can determine that the possible values for A, B, and C are 0, 1, and 2.
Therefore, one possible solution for the cryptogram AB×BA = ACB is 10×01 = 010.
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[tex]{\huge{\colorbox {lavenderblush}{✯Answer✯࿐}}}[/tex]
Solution:
AB represent a 2 digit number with A
at 10s place and B at units place. We are multiplying AB with AB.
• A and B can take any values from 0 to 9.
But If We multiply B by B to get B itself at the units place of the product,
⚫ B can be 0, 1, 5, 6.
• Also A should be at the 10s place, therefore middle term should not have any carry over.
Middle term is AB + AB = C
Therefore B cannot be 5 or 6.
Also A cannot be 5 or 6.
. Therefore A and B can be 0 or 1
If we assume B and C to be different numbers, B cannot be 0, as this makes C also 0.
Therefore, B = 1
. Then A also 1 • C=AB+ BA = 2
Answer:
Sup Kakashi
Step-by-step explanation:
To solve the cryptogram AB×BA = ACB, we need to find the values of A, B, and C that satisfy the equation.
Let's break down the equation: AB×BA = ACB.
We can see that the product of AB and BA equals ACB.
Let's assign variables to each digit: A, B, and C.
To find the values, we can start by multiplying the ones digit of AB (B) with the ones digit of BA (A). This should give us the ones digit of ACB.
From the equation, we have B × A = C.
Now, let's look at the tens digit. When we multiply the tens digit of AB (A) with the ones digit of BA (A), we should get the tens digit of ACB.
From the equation, we have A × A = A.
Lastly, let's consider the hundreds digit. The hundreds digit of ACB is equal to the product of the tens digit of AB (B) and the tens digit of BA (B).
From the equation, we have B × B = B.
Based on this analysis, we can determine that the possible values for A, B, and C are 0, 1, and 2.
Therefore, one possible solution for the cryptogram AB×BA = ACB is 10×01 = 010.