3 and 1/2
Step-by-step explanation:
quadratic formula =-b +- underroot b2 _ 4ac /2a
then,
b=-7 & a= 2 & c = 3
x =-(-7 )+- under root (-7 whole sq.) - 4×2×3 / 4
× = 7 +- under root 49 -24 / 4
×= 7+- under root 25 /4
x=7+-5 /4
7+5/4 = 12/4 = 3
7-5 /4 = 2/4 =1/2
Find root of the Quadratic equation by Quadratic formula 2x² – 7x + 3 = 0.
The quadratic equation 2x² – 7x + 3 = 0.
The root of the given quadratic equation by quadratic formula.
On comparing this equation with
ax² + bx + c = 0, we get
By using quadratic formula, we get
[tex]{ \boxed{ \sf \large \color{red}x = - b± \frac{ \sqrt{{}b2 - 4ac} }{2a} }}[/tex]
[tex] \sf \large⇒x = 7± \frac{ \sqrt{{49 - 24}} }{4} \\ \\ \\ \sf \large⇒x = 7± \frac{ \sqrt{{}25} }{4} \: \: \: \: \: \: \: \: \: \: [/tex]
[tex] \sf \large⇒x = 7± \frac{5}{4} [/tex]
[tex] \sf \large⇒x = \frac{7 + 5}{4} [/tex]
[tex] \sf \large⇒x = \frac{12}{4} \: (or) \: \frac{2}{4} [/tex]
[tex] \sf \large⇒x = 3 \: (or) \: \frac{1}{2} [/tex]
[tex]{ \boxed{ \sf \large \color{blue} \therefore x = 3 \: (or) \: \frac{1}{2} .}}[/tex]
Hope you have satisfied. ⚘
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Answers & Comments
3 and 1/2
Step-by-step explanation:
quadratic formula =-b +- underroot b2 _ 4ac /2a
then,
b=-7 & a= 2 & c = 3
x =-(-7 )+- under root (-7 whole sq.) - 4×2×3 / 4
× = 7 +- under root 49 -24 / 4
×= 7+- under root 25 /4
x=7+-5 /4
7+5/4 = 12/4 = 3
7-5 /4 = 2/4 =1/2
Verified answer
Question:-
Find root of the Quadratic equation by Quadratic formula 2x² – 7x + 3 = 0.
Given:-
The quadratic equation 2x² – 7x + 3 = 0.
To Find:-
The root of the given quadratic equation by quadratic formula.
Solution:-
On comparing this equation with
ax² + bx + c = 0, we get
By using quadratic formula, we get
[tex]{ \boxed{ \sf \large \color{red}x = - b± \frac{ \sqrt{{}b2 - 4ac} }{2a} }}[/tex]
[tex] \sf \large⇒x = 7± \frac{ \sqrt{{49 - 24}} }{4} \\ \\ \\ \sf \large⇒x = 7± \frac{ \sqrt{{}25} }{4} \: \: \: \: \: \: \: \: \: \: [/tex]
[tex] \sf \large⇒x = 7± \frac{5}{4} [/tex]
[tex] \sf \large⇒x = \frac{7 + 5}{4} [/tex]
[tex] \sf \large⇒x = \frac{12}{4} \: (or) \: \frac{2}{4} [/tex]
[tex] \sf \large⇒x = 3 \: (or) \: \frac{1}{2} [/tex]
Answer:-
[tex]{ \boxed{ \sf \large \color{blue} \therefore x = 3 \: (or) \: \frac{1}{2} .}}[/tex]
Hope you have satisfied. ⚘